p^2-2p-5.5=0

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Solution for p^2-2p-5.5=0 equation: 



p^2-2p-5.5=0

a = 1; b = -2; c = -5.5;
Δ = b2-4ac
Δ = -22-4·1·(-5.5)
Δ = 26
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{26}}{2*1}=\frac{2-\sqrt{26}}{2}
$


$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{26}}{2*1}=\frac{2+\sqrt{26}}{2}
$

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